Antiderivative of |sin(u)|: Breaking it Down and Finding the Solution

ln|sinu|+c

The expression ln|sinu| + c represents the antiderivative of the function f(u) = |sinu|, where ln denotes the natural logarithm and c is a constant

The expression ln|sinu| + c represents the antiderivative of the function f(u) = |sinu|, where ln denotes the natural logarithm and c is a constant.

To find the antiderivative of f(u), we can break it into two cases: when sinu is positive and when sinu is negative.

Case 1: sinu > 0
In this case, |sinu| equals sinu. Therefore, we can write f(u) = sinu.
The antiderivative of sinu is -cosu. So, the antiderivative of f(u) in this case is -cosu + c.

Case 2: sinu < 0 In this case, |sinu| equals -sinu. Therefore, we can write f(u) = -sinu. The antiderivative of -sinu is cosu. So, the antiderivative of f(u) in this case is cosu + c. Combining both cases, the antiderivative of f(u) = |sinu| is given by: ln|sinu| + c = - cosu + c (when sinu > 0) or
cosu + c (when sinu < 0) Note: The constant c represents the constant of integration and can be chosen arbitrarily.

More Answers:

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Mastering Integration: Sec u + c Simplified – Rules and Steps
Understanding the Step-By-Step Breakdown of the Math Expression ln |sec u| + c

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