Probability of Picking a Green Marble without Replacing the Blue Marble in a Hat

Solve the word problem.There are 8 red, 5 blue, and 2 green marbles in a hat. Without looking, you picked a blue marble. Without putting the blue marble back, what is the probability of picking a green marble?

To solve this problem, we first need to determine the total number of marbles in the hat after picking a blue marble

To solve this problem, we first need to determine the total number of marbles in the hat after picking a blue marble.

Initially, there are a total of 8 red marbles, 5 blue marbles, and 2 green marbles, for a total of 8 + 5 + 2 = 15 marbles.

After picking a blue marble, you have not put it back into the hat, so there are now 15 – 1 = 14 marbles left in the hat.

Out of these 14 marbles, there are still 2 green marbles, so the probability of picking a green marble is given by dividing the number of green marbles by the total number of marbles left in the hat:

P(picking a green marble) = number of green marbles / total number of marbles left in the hat

P(picking a green marble) = 2 / 14

Simplifying this fraction gives:

P(picking a green marble) = 1 / 7

Therefore, the probability of picking a green marble without putting the blue marble back is 1/7.

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