∫sin u du
To evaluate the integral ∫sin(u)du, we can use the trigonometric identity:
∫sin(u)du = -cos(u) + C,
where C is the constant of integration
To evaluate the integral ∫sin(u)du, we can use the trigonometric identity:
∫sin(u)du = -cos(u) + C,
where C is the constant of integration.
Therefore, the integral of sin(u) with respect to u is -cos(u) + C.
More Answers:
[next_post_link]