When chlorine gas (Cl2) is present in excess with hydroxide ions (OH-), it will remove the proton from the hydroxide ion via a redox reaction and form hypochlorite ion (ClO-) and chloride ion (Cl-) as products. The reaction can be written as:
Cl2 + 2OH- → ClO- + Cl- + H2O
Therefore, the reaction of Cl2 excess/ OH- will remove a hydrogen ion (H+) from OH-, producing water H2O along with ClO- and Cl- ions.
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