(x-6)(x-3)
x²-9x+18
To expand the expression (x-6)(x-3), we need to use the distributive law.
First, let’s multiply x by each term in the second parentheses:
x(x-3) = x^2 – 3x
Next, let’s multiply -6 by each term in the second parentheses:
-6(x-3) = -6x + 18
Now, we can combine these two products by adding them together:
(x-6)(x-3) = x^2 – 3x – 6x + 18
Finally, we can simplify by combining like terms to get the final answer:
(x-6)(x-3) = x^2 – 9x + 18
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