(x+1)(x-7)
x²-6x-7
To multiply (x+1)(x-7), we can use the FOIL method which stands for First, Outer, Inner, and Last.
First, we multiply the first term of each set of parentheses:
x * x = x^2
Next, we multiply the outer terms of each set of parentheses:
x * -7 = -7x
Then, we multiply the inner terms of each set of parentheses:
1 * x = x
Finally, we multiply the last terms of each set of parentheses:
1 * -7 = -7
Now we can combine all the terms:
x^2 – 7x + x – 7
Simplifying:
x^2 – 6x – 7
Therefore, (x+1)(x-7) = x^2 – 6x – 7.
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