(3x+1)(x+3)
3x²+10x+3
To expand (3x+1)(x+3), you need to use the distributive property. This means that you multiply each term of the first expression by each term of the second expression, and then combine like terms.
(3x+1)(x+3) = 3x(x+3) + 1(x+3)
Now, multiply each term:
= 3x(x) + 3x(3) + 1(x) + 1(3)
Simplify by combining like terms:
= 3x^2 + 9x + x + 3
= 3x^2 + 10x + 3
So, (3x+1)(x+3) expands to 3x^2 + 10x + 3.
More Answers:
[next_post_link]