-cosx + C
∫sinxdx
Question: What is the integral of -cosx?
Solution:
The integral of -cosx can be found as follows:
We know that the derivative of sinx is cosx, therefore, we can apply the reverse chain rule here.
Let u = sinx, then du/dx = cosx
Therefore,
∫-cosx dx = -∫du
= -sinx + C
Hence, the integral of -cosx is -sinx + C, where C is the constant of integration.
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