∫sin x dx
-cos x + c
To integrate sin x dx, we can use integration by parts or the substitution method.
Method 1: Integration by Parts
Let u = sin x and dv = dx. Then, du/dx = cos x and v = x.
Using the formula for integration by parts, we have:
∫sin x dx = -cos x + ∫cos x dx
We can integrate cos x using the same method. Let u = cos x and dv = dx. Then, du/dx = -sin x and v = x.
Continuing with integration by parts, we have:
∫sin x dx = -cos x + sin x + C, where C is the constant of integration.
Therefore, the antiderivative of sin x is -cos x + sin x + C.
Method 2: Substitution
We can also integrate sin x using substitution. Let u = cos x, then du/dx = -sin x and dx = du/-sin x.
Substituting in the integral, we have:
∫sin x dx = ∫-du/u
Integrating -du/u gives us:
– ln|u| + C
Substituting back u = cos x, we have:
– ln|cos x| + C
Therefore, the antiderivative of sin x is – ln|cos x| + C.
Both methods give us the antiderivative of sin x in different forms.
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