1+cot^2
csc^2
We can simplify 1 + cot² using trigonometric identities.
Recall that cotangent is the reciprocal of tangent:
cot θ = 1/tan θ
Therefore, we can write:
1 + cot² θ = 1 + (1/tan² θ)
We can then use the Pythagorean identity to express tan² θ in terms of sin² θ and cos² θ:
tan² θ = sin² θ / cos² θ
Substituting this into the expression for 1 + cot² θ, we get:
1 + cot² θ = 1 + (1 / (sin² θ / cos² θ))
Simplifying this expression by taking the reciprocal of the fraction inside the parenthesis, we get:
1 + cot² θ = 1 + (cos² θ / sin² θ)
Now we can simplify further by adding the fractions:
1 + cot² θ = (sin² θ + cos² θ) / sin² θ
Using the Pythagorean identity again, we know that sin² θ + cos² θ = 1, so we can substitute:
1 + cot² θ = 1 / sin² θ
Finally, we can use the reciprocal identity for sine:
1 + cot² θ = csc² θ
Therefore, 1 + cot² θ simplifies to csc² θ.
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