derv (ln u)
(u’)/u
To find the derivative of ln(u), where u is a function of some variable x.
Using the chain rule of differentiation, we have:
d/dx [ln(u)] = (d/du [ln(u)]) (du/dx)
Now, d/du [ln(u)] = 1/u, and du/dx is simply the derivative of the function u with respect to x.
Therefore, we can rewrite the derivative of ln(u) as:
d/dx [ln(u)] = (1/u) (du/dx)
So, the final answer is (1/u) (du/dx).
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