Learn How To Expand (X+7)(X-4) Using The Foil Method With Easy Steps And Get The Solution X^2 + 3X – 28

(x+7)(x-4)

x²+3x-28

To expand (x+7)(x-4), we can use the FOIL method, which stands for First, Outer, Inner, Last. This method helps us remember which terms we need to multiply together:

– First: Multiply the first terms of both expressions, which gives us x * x = x^2.
– Outer: Multiply the outer terms, which gives us x * (-4) = -4x.
– Inner: Multiply the inner terms, which gives us 7 * x = 7x.
– Last: Multiply the last terms of both expressions, which gives us 7 * (-4) = -28.

Now we can combine these four terms to get our final answer:

(x+7)(x-4) = x^2 – 4x + 7x – 28

Simplifying this expression further, we can combine the -4x and 7x terms to get 3x:

(x+7)(x-4) = x^2 + 3x – 28

Therefore, the expanded form of (x+7)(x-4) is x^2 + 3x – 28.

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