Find the composition of the function.f(x)=x^1/3 and g(x)=x Find g(f(x)).
x^(1/6)
To find g(f(x)), we need to first find the output of f(x) and then use that output as the input for g(x).
Given,
f(x) = x^(1/3)
g(x) = x
Now, the output of f(x) for a given input x is the cube-root of x.
So,
f(x) = cube-root of x
Using this as input for g(x), we get:
g(f(x)) = g(cube-root of x)
= cube-root of x (since g(x) = x)
Therefore, g(f(x)) = cube-root of x
Hence, the composition of the given functions is g(f(x)) = cube-root of x.
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