cscx cotx dx
-cscx + C
We can use substitution method to solve the integral of cscx cotx dx. Let u = cotx, then du = -csc^2x dx.
Rewriting the integral in terms of u, we get:
∫ cscx cotx dx = ∫ -du
Integrating the right-hand side, we get:
– ∫ du = -u + C
Substituting back in for u, we get:
∫ cscx cotx dx = -cotx + C
Therefore, the antiderivative of cscx cotx dx equals -cotx + C.
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