sec^2 dx
tanx + C
The integral of sec^2 x dx is:
∫sec^2 x dx = tan x + C
Where C is the constant of integration.
To prove this, we need to use a trigonometric identity. The identity states that:
1 + tan^2 x = sec^2 x
Rearranging the equation, we get:
tan^2 x = sec^2 x – 1
Dividing both sides of the equation by sec^2 x, we get:
tan^2 x / sec^2 x = sec^2 x / sec^2 x – 1 / sec^2 x
tan^2 x / sec^2 x = 1 – cos^2 x / sin^2 x
Since tan x = sin x / cos x, we can substitute and get:
sin^2 x / cos^2 x / sec^2 x = 1 – cos^2 x / sin^2 x
Simplifying the left side:
sin^2 x / cos^2 x * cos^2 x / 1 = sin^2 x
Hence:
sin^2 x = sin^2 x
This proves the identity that we will use to obtain the integral of sec^2 x dx:
∫sec^2 x dx = ∫(1 + tan^2 x) dx
Using the power rule of integration, we get:
∫sec^2 x dx = tan x + C
Where C is the constant of integration.
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