secx tanx dx
secx + c
We can solve this integral by substitution. Let u = sec(x).
Then, du/dx = sec(x)tan(x), and we can rewrite the integral in terms of u as follows:
∫ sec(x)tan(x) dx = ∫ du
Integrating both sides, we obtain:
∫ sec(x)tan(x) dx = ln|sec(x) + tan(x)| + C
where C is the constant of integration.
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