d/dx(tanx)
sec²x
To find the derivative of tan(x) with respect to x, we use the quotient rule.
Let f(x) = sin(x) and g(x) = cos(x), then tan(x) = f(x) / g(x).
Using the quotient rule:
[d/dx (tan(x))] = [ g(x) d/dx(f(x)) – f(x) d/dx(g(x)) ] / [g(x)]^2
Now, we find the derivatives of f(x) and g(x):
d/dx (sin(x)) = cos(x) and d/dx (cos(x)) = -sin(x)
Substituting these values in the above equation, we get:
[d/dx (tan(x))] = [cos(x)cos(x) – sin(x)(-sin(x))] / [cos(x)]^2
Simplifying the expression, we get:
[d/dx (tan(x))] = [cos^2(x) + sin^2(x)] / [cos^2(x)]
[d/dx (tan(x))] = 1 / [cos^2(x)]
Thus, the derivative of tan(x) with respect to x is (1 / cos^2(x)).
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