Mastering Binomial Expansion: The Optimized Form Of (1/3)(3X + 4)^3

y = (1/3)(3x + 4)^3

y’ = 27x^2 + 72x + 48

To expand the expression y = (1/3)(3x + 4)^3, we can begin by applying the binomial expansion formula. This formula is given by:

(a + b)^n = nC0(a^n)b^0 + nC1(a^n-1)b^1 + nC2(a^n-2)b^2 + … + nCn(a^0)b^n

Where nCi is the binomial coefficient, given by n!/(i!(n-i)!).

Using this formula, we can write:

(3x + 4)^3 = 3C0(3x)^3 4^0 + 3C1(3x)^2 4^1 + 3C2(3x)^1 4^2 + 3C3(3x)^0 4^3

Simplifying this expression, we get:

(3x + 4)^3 = 27x^3 + 108x^2 + 144x + 64

Now we can substitute this expression back into the original equation:

y = (1/3)(27x^3 + 108x^2 + 144x + 64)

Expanding the expression further, we get:

y = 9x^3 + 36x^2 + 48x + 21.333

Therefore, the expanded form of y = (1/3)(3x + 4)^3 is y = 9x^3 + 36x^2 + 48x + 21.333.

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