(x + 9)(x – 2)
x² + 7x – 18
This is a multiplication of two binomials: $(x + 9)$ and $(x – 2)$. To find the product, we can use FOIL method which stands for:
F – First terms: multiply the first term of each binomial – $x$ in the first binomial and $x$ in the second binomial:
$x * x = x^2$.
O – Outer terms: multiply the outer term of each binomial (the term that comes first in each binomial) – $x$ in the first binomial and $-2$ in the second binomial:
$x * (-2) = -2x$.
I – Inner terms: multiply the inner term of each binomial (the term that comes second in each binomial) – $9$ in the first binomial and $x$ in the second binomial:
$9 * x = 9x$.
L – Last terms: multiply the last term of each binomial – $9$ in the first binomial and $-2$ in the second binomial:
$9 * (-2) = -18$.
Now, we can put these terms together to form the final expression:
$(x + 9) * (x – 2) = x^2 – 2x + 9x – 18 = x^2 + 7x – 18$.
Therefore, the expanded form of the expression $(x+9)(x-2)$ is $x^2+7x-18$.
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