What are the first five terms of the sequence defined by the given function?f(n) = 2n − 8
To find the first five terms of the sequence defined by the function f(n) = 2n – 8, we can substitute different values of n into the function and calculate the corresponding values of f(n)
To find the first five terms of the sequence defined by the function f(n) = 2n – 8, we can substitute different values of n into the function and calculate the corresponding values of f(n). Let’s do that:
When n = 1, we have f(1) = 2(1) – 8 = -6.
When n = 2, we have f(2) = 2(2) – 8 = -4.
When n = 3, we have f(3) = 2(3) – 8 = -2.
When n = 4, we have f(4) = 2(4) – 8 = 0.
When n = 5, we have f(5) = 2(5) – 8 = 2.
So, the first five terms of the sequence defined by f(n) = 2n – 8 are: -6, -4, -2, 0, 2.
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