How to Find the Integral of cot(x) Using Substitution | Step-by-Step Guide

∫(cotx)dx

To find the integral of cot(x) dx, we can use a technique called substitution

To find the integral of cot(x) dx, we can use a technique called substitution.

Let’s start by carefully considering the integral:
∫(cot(x))dx

We can rewrite cot(x) as cos(x)/sin(x):
∫(cos(x)/sin(x))dx

Now, let’s substitute u = sin(x):
du/dx = cos(x)

So, we have:
∫(du/u)dx

Now, substitute back in x for u using x = arcsin(u):
∫(dx/asin(x))

To simplify this further, we can rewrite the denominator in terms of x:
∫(dx/(x/sqrt(1 – x^2)))

Now, we can rewrite this as:
∫(sqrt(1 – x^2)/x)dx

This integral requires another technique called trigonometric substitution. Consider substituting x = sin(θ):
dx = cos(θ)dθ
sqrt(1 – x^2) = sqrt(1 – sin^2(θ)) = sqrt(cos^2(θ)) = cos(θ)

Now, we have:
∫(cos(θ)/sin(θ))cos(θ)dθ

Simplify this as:
∫(cos^2(θ)/sin(θ))dθ

Using the trig identity cos^2(θ) = 1 – sin^2(θ), we can substitute to get:
∫((1 – sin^2(θ))/sin(θ))dθ

Simplify further:
∫(1/sin(θ) – sin(θ)/sin(θ))dθ
∫(cosec(θ) – 1)dθ

Finally, we have:
∫cosec(θ)dθ – ∫dθ

Now, let’s integrate each term separately:
∫cosec(θ)dθ = ln|cosec(θ) + cot(θ)| + C1
∫dθ = θ + C2

So, the overall integral becomes:
ln|cosec(θ) + cot(θ)| – θ + C

Now, substitute back x for θ:
ln|cosec(x) + cot(x)| – x + C

Therefore, the integral of the cot(x) function is:
∫(cot(x))dx = ln|cosec(x) + cot(x)| – x + C, where C is the constant of integration.

More Answers:

[next_post_link]