f(0) = 9 , f(n) = f(n-1)/3for n ≥ 1
To find the value of f(1), we can use the given recursive definition:
f(n) = f(n-1)/3 for n ≥ 1
Since we’re looking for f(1), we can substitute n = 1 into the definition:
f(1) = f(1-1)/3
f(1) = f(0)/3
We are given that f(0) = 9, so substituting this value:
f(1) = 9/3
f(1) = 3
Therefore, f(1) = 3
To find the value of f(1), we can use the given recursive definition:
f(n) = f(n-1)/3 for n ≥ 1
Since we’re looking for f(1), we can substitute n = 1 into the definition:
f(1) = f(1-1)/3
f(1) = f(0)/3
We are given that f(0) = 9, so substituting this value:
f(1) = 9/3
f(1) = 3
Therefore, f(1) = 3.
To find the value of f(2), we can again use the recursive definition:
f(n) = f(n-1)/3 for n ≥ 1
Substituting n = 2:
f(2) = f(2-1)/3
f(2) = f(1)/3
We have already found the value of f(1) to be 3. Substituting this value:
f(2) = 3/3
f(2) = 1
Therefore, f(2) = 1.
Continuing this pattern, we can find the values of f(3), f(4), and so on. Each subsequent value of f(n) will be one-third of the previous value.
More Answers:
[next_post_link]