derivative of tan^-1
The derivative of the inverse tangent function, also written as “tan^(-1)” or “arctan,” can be found using calculus techniques
The derivative of the inverse tangent function, also written as “tan^(-1)” or “arctan,” can be found using calculus techniques. Let’s calculate it step by step.
We start by recalling the derivative of the inverse function. If we have a function y = f(x) and its inverse function is x = f^(-1)(y), then the derivative of the inverse function is given by:
dy/dy = 1 / (dx/dy)
Applying this concept to the inverse tangent function, we have:
Let y = tan^(-1)(x)
To find dy/dx (derivative of y with respect to x), we’ll differentiate both sides of the above equation.
d/dx(y) = d/dx(tan^(-1)(x))
Now, we need to apply the chain rule. The chain rule allows us to differentiate compositions of functions.
The derivative of the inverse tangent function can be expressed as:
dy/dx = (d/dx(tan^(-1)(x))) / (dx/dx)
Since dx/dx is simply 1, the chain rule simplifies to:
dy/dx = d/dx(tan^(-1)(x))
To differentiate the inverse tangent function, we can use the fact that:
d/dx(tan^(-1)(x)) = 1 / (1 + x^2)
Therefore, the derivative of tan^(-1)(x) is:
dy/dx = 1 / (1 + x^2)
And that’s the final answer! The derivative of the inverse tangent function is 1 / (1 + x^2).
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