Solving the Equation y’ = 14x | Understanding the First-Order Derivative and Function Integration

y’=14x

The equation y’ = 14x represents a first-order derivative

The equation y’ = 14x represents a first-order derivative. In mathematics, this notation represents the derivative of a function y with respect to x, or the rate of change of y with respect to x.

In this specific case, y’ = 14x means that the rate of change of y with respect to x is given by the expression 14x. This implies that as x changes, y changes at a rate that is proportional to x, with a constant of proportionality equal to 14.

To find the function y that satisfies this equation, we need to integrate both sides with respect to x. Integrating y’ = 14x gives:

∫y’ dx = ∫14x dx

y = 14∫x dx

Now, we can integrate the right hand side. The integral of x with respect to x is (x^2)/2. Therefore:

y = 14 * (x^2)/2 + C

where C represents a constant of integration. The constant C accounts for potential initial conditions or boundary conditions that are not given in the equation y’ = 14x.

In summary, the solution to the differential equation y’ = 14x is a family of functions given by y = (7/2) * x^2 + C, where C is the constant of integration.

More Answers:
Solving a First Order ODE | y’ = 2e^x using Separation of Variables
Solving a Differential Equation | dy/dx = 7/x³
How to Simplify the Given Expression | Expand Numerator and Simplify Denominator

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