Finding the Original Function from its Derivative | Integrating 2xe^2 to Obtain y = x^2e^2 + C

y’=2xe²

The given expression, y’ = 2xe^2, represents the derivative of a function y with respect to x

The given expression, y’ = 2xe^2, represents the derivative of a function y with respect to x. To find the original function y, we need to integrate the given expression with respect to x.

To begin, let’s separate the variables dx and dy:

dy = 2xe^2 dx

Now, we can integrate both sides of the equation:

∫ dy = ∫ (2xe^2) dx

Integrating the left side with respect to y gives us:

y = ∫ (2xe^2) dx

To integrate the right side, we can use the power rule for integration and also take into account the exponential function.

∫ (2xe^2) dx = 2 ∫ (x e^2) dx

Applying the power rule, we integrate x to get (1/2)x^2, and treating e^2 as a constant, we get:

2 ∫ (x e^2) dx = 2 * (1/2)x^2 * e^2 + C

Where C is the constant of integration.

Simplifying further:

y = x^2 * e^2 + C

So, the original function y, that corresponds to the derivative y’ = 2xe^2, is y = x^2 * e^2 + C.

More Answers:
Solving a Differential Equation | dy/dx = 7/x³
How to Simplify the Given Expression | Expand Numerator and Simplify Denominator
Solving the Equation y’ = 14x | Understanding the First-Order Derivative and Function Integration

Error 403 The request cannot be completed because you have exceeded your quota. : quotaExceeded

Share:

Recent Posts

Mathematics in Cancer Treatment

How Mathematics is Transforming Cancer Treatment Mathematics plays an increasingly vital role in the fight against cancer mesothelioma. From optimizing drug delivery systems to personalizing

Read More »