d/dx(tanx)
sec²x
To find the derivative of tanx with respect to x, we can use the quotient rule. The quotient rule states that if we have a function in the form of f(x) = g(x)/h(x), then its derivative is given by:
f'(x) = (g'(x)h(x) – g(x)h'(x))/(h(x))^2
In this case, g(x) = sinx and h(x) = cosx.
Let’s find the derivatives of g(x) and h(x) first:
g'(x) = cosx (the derivative of sinx is cosx),
h'(x) = -sinx (the derivative of cosx is -sinx).
Now, we can substitute the values into the quotient rule formula:
f'(x) = (cosx * cosx – sinx * (-sinx))/(cosx)^2
= (cos^2 x + sin^2 x)/(cosx)^2
Using the trigonometric identity sin^2 x + cos^2 x = 1, we can simplify further:
f'(x) = 1/(cosx)^2
Therefore, the derivative of tanx with respect to x is 1/(cosx)^2.
More Answers:
[next_post_link]