Determining the Same Network IPv4 Address for Host-A with IP Address 172.16.4.100 and Subnet Mask 255.255.0.0

Host-A has the IPv4 address and subnet mask 172.16.4.100, 255.255.0.0, Which of the following IPv4 addresses would be on the same network as Host-A? (Choose all that apply) A)172.16.4.99 B)172.16.0.1 C)172.17.4.99 D)172.17.4.1 E)172.18.4.1

To determine which of the following IPv4 addresses would be on the same network as Host-A with the given IP address and subnet mask, we need to perform a bitwise logical AND operation between the IP address and the subnet mask.

The result should match the network address of Host-A.

The binary representation of the given IP address (172.16.4.100) and subnet mask (255.255.0.0) are as follows:

IP address: 10101100.00010000.00000100.01100100
Subnet mask: 11111111.11111111.00000000.00000000

Performing the bitwise AND operation, we get:

10101100.00010000.00000100.01100100 (IP address)
AND
11111111.11111111.00000000.00000000 (Subnet mask)
————————————————–
10101100.00010000.00000000.00000000

The resulting network address is 172.16.0.0.

Now, let’s check the given IPv4 addresses:

A) 172.16.4.99
Binary: 10101100.00010000.00000100.01100011

This IP address does not match the network address of Host-A (172.16.0.0).

B) 172.16.0.1
Binary: 10101100.00010000.00000000.00000001

This IP address matches the network address of Host-A (172.16.0.0).

C) 172.17.4.99
Binary: 10101100.00010001.00000100.01100011

This IP address does not match the network address of Host-A (172.16.0.0).

D) 172.17.4.1
Binary: 10101100.00010001.00000100.00000001

This IP address does not match the network address of Host-A (172.16.0.0).

E) 172.18.4.1
Binary: 10101100.00010010.00000100.00000001

This IP address does not match the network address of Host-A (172.16.0.0).

Therefore, the only IPv4 address on the same network as Host-A is B) 172.16.0.1.

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